warning C4996: ‘std::_Copy_impl’: Function call with parameters that may be

编译protobuffer ，出现了两个问题

1.vs加载项目后，会发现min函数 没有引入头文件   #include ；

2.vs2013编译测试类的时候，抛出了以下异常：

warning C4996: ‘std::_Copy_impl’: Function call with parameters that may be unsafe – this call relies on the caller to check that the passed values are correct. To disable this warning, use -D_SCL_SECURE_NO_WARNINGS. See documentation on how to use Visual C++ ‘Checked Iterators’

解决的方案请看:http://choorucode.com/2010/08/30/visual-c-c4996-warning-on-copy-with-array-parameters/

protobuffer 中抛出异常的头文件是repeated_field.h中第708行，修改后的代码如下：

解决use -D_SCL_SECURE_NO_WARNINGS的问题
分类： 错误处理 2014-06-06 19:01 4083人阅读 评论(1) 收藏 举报
vc2012报错了：
1>c:\program files (x86)\microsoft visual studio11.0\vc\include\xutility(2176): error C4996: 'std::_Copy_impl': Function callwith parameters that may be unsafe - this call relies on the caller to checkthat the passed values are correct. To disable this warning, use-D_SCL_SECURE_NO_WARNINGS. See documentation on how to use Visual C++ 'CheckedIterators'
 
 
 
加入预处理器(项目属性----C/C++----预处理----预处理器定义)：
_SCL_SECURE_NO_WARNINGS
 
 
 
即可解决

大家看看我的这个警告？怎么解决

bool ranking_manager::split_string(std::vector &vec,std::string str,const char *p)
{
    s_uint32 number;
    std::vector strvec_;
 
    if(vec.size()<=0 || str.length() == 0)
        return false;
    //使用boost自带进行字符串的分割
    boost::split(strvec_, str, boost::is_any_of(p), boost::token_compress_on);
    //类型转换string转换为int
    std::vector::iterator it  = strvec_.begin();
    for(it;it!= strvec_.end();++it)
    {
        std::stringstream stream;
        stream << *it;
        stream >> number;
        vec.push_back(number);
    }
    strvec_.clear();
    return true;
}

e:\soft\vs2010\vc\include\xutility(2239): warning C4996: 'std::_Copy_impl': Function call with parameters that may be unsafe - this call relies on the caller to check that the passed values are correct. To disable this warning, use -D_SCL_SECURE_NO_WARNINGS. See documentation on how to use Visual C++ 'Checked Iterators'
2>          e:\soft\vs2010\vc\include\xutility(2224) : 参见“std::_Copy_impl”的声明
2>          d:\d3\project\source\tools\boost_1_51_0\boost\algorithm\string\detail\classification.hpp(102): 参见对正在编译的函数 模板 实例化“_OutIt std::copy(_InIt,_InIt,_OutIt)”的引用
2>          with
2>          [
2>              _OutIt=char *,
2>              _InIt=const char *
2>          ]
2>          d:\d3\project\source\tools\boost_1_51_0\boost\algorithm\string\classification.hpp(206): 参见对正在编译的函数 模板 实例化“boost::algorithm::detail::is_any_ofF::is_any_ofF>(const RangeT &)”的引用
2>          with
2>          [
2>              CharT=char,
2>              IteratorT=const char *,
2>              RangeT=boost::iterator_range
2>          ]
2>          d:\d3\project\source\server\game\src\logic\ranking\ranking_manager.cpp(233): 参见对正在编译的函数 模板 实例化“boost::algorithm::detail::is_any_ofF boost::algorithm::is_any_of(const RangeT &)”的引用
2>          with
2>          [
2>              CharT=char,
2>              RangeT=const char *
2>          ]e:\soft\vs2010\vc\include\xutility(2239): warning C4996: 'std::_Copy_impl': Function call with parameters that may be unsafe - this call relies on the caller to check that the passed values are correct. To disable this warning, use -D_SCL_SECURE_NO_WARNINGS. See documentation on how to use Visual C++ 'Checked Iterators'
2>          e:\soft\vs2010\vc\include\xutility(2224) : 参见“std::_Copy_impl”的声明
2>          d:\d3\project\source\tools\boost_1_51_0\boost\algorithm\string\detail\classification.hpp(102): 参见对正在编译的函数 模板 实例化“_OutIt std::copy(_InIt,_InIt,_OutIt)”的引用
2>          with
2>          [
2>              _OutIt=char *,
2>              _InIt=const char *
2>          ]
2>          d:\d3\project\source\tools\boost_1_51_0\boost\algorithm\string\classification.hpp(206): 参见对正在编译的函数 模板 实例化“boost::algorithm::detail::is_any_ofF::is_any_ofF>(const RangeT &)”的引用
2>          with
2>          [
2>              CharT=char,
2>              IteratorT=const char *,
2>              RangeT=boost::iterator_range
2>          ]
2>          d:\d3\project\source\server\game\src\logic\ranking\ranking_manager.cpp(233): 参见对正在编译的函数 模板 实例化“boost::algorithm::detail::is_any_ofF boost::algorithm::is_any_of(const RangeT &)”的引用
2>          with
2>          [
2>              CharT=char,
2>              RangeT=const char *
2>          ]

这个要怎么改，没看明白？

#define _SCL_SECURE_NO_WARNINGS



 

I got this warning message.. but i dont know what/where the problem is..!

includes

#pragma warning(push)
#pragma warning(disable:4996)
#include <boost/archive/iterators/base64_from_binary.hpp>
#include <boost/archive/iterators/insert_linebreaks.hpp>
#include <boost/archive/iterators/transform_width.hpp>
#include <boost/archive/iterators/ostream_iterator.hpp>
#pragma warning(pop)
and the warning

1>c:\program files (x86)\microsoft visual studio 10.0\vc\include\xutility(2227): warning C4996: 'std::_Copy_impl': Function call with parameters that may be unsafe - this call relies on the caller to check that the passed values are correct. To disable this warning, use -D_SCL_SECURE_NO_WARNINGS. See documentation on how to use Visual C++ 'Checked Iterators'
1>          c:\program files (x86)\microsoft visual studio 10.0\vc\include\xutility(2212): Siehe Deklaration von 'std::_Copy_impl'
1>          c:\users\perlig\documents\visual studio 2010\projects\restmanager\restmanager\**http.cpp(257)**: Siehe Verweis auf die Instanziierung der gerade kompilierten Funktions-template "_OutIt std::copy<boost::archive::iterators::insert_linebreaks<Base,N>,boost::archive::iterators::ostream_iterator<Elem>>(_InIt,_InIt,_OutIt)".
1>          with
1>          [
1>              _OutIt=boost::archive::iterators::ostream_iterator<char>,
1>              Base=boost::archive::iterators::base64_from_binary<boost::archive::iterators::transform_width<const char *,6,8>>,
1>              N=76,
1>              Elem=char,
1>                _InIt=boost::archive::iterators::insert_linebreaks<boost::archive::iterators::base64_from_binary<boost::archive::iterators::transform_width<const char *,6,8>>,76>
1>          ]
the code occur in line 257 as the warning message says. but i´m not able to fix it because i not know what is wrong..

string data contains a "user:password" string for basic auth via http.

http.cpp(257):

// typdef, prepare
using namespace boost::archive::iterators;
stringstream os;
typedef
    insert_linebreaks<         // insert line breaks every 72 characters
        base64_from_binary<    // convert binary values ot base64 characters
            transform_width<   // retrieve 6 bit integers from a sequence of 8 bit bytes
                const char *,
                6,
                8
            >
        >
        ,76
    >
    base64_text; // compose all the above operations in to a new iterator

// encrypt
#pragma warning(push)
#pragma warning(disable:4996)
copy( //<<<<<------ LINE 257
    base64_text(data.c_str()),
    base64_text(data.c_str() + data.size()),
    boost::archive::iterators::ostream_iterator<char>(os)
);
#pragma warning(pop)
anybody got any idea?

I think you know what is the meaning of the warning but first I describe the warning and then say what to do to get rid of it. Microsoft implemented a new security enabled set of function in its CRT, STL, MFC, ... and mark old version of those functions as deprecated to provide a hint for you that you should migrate to new secure version. so it say std::copy is unsafe!! how? as follow:

char storage[ 10 ], *p = storage;
std::copy( std::istream_iterator<int>(std::cin), std::istream_iterator<int>(), p );
Now what will happened if user input more than 10 int? the memory will be overwritten and you corrupted your memory.

Using boost::archive::iterators::ostream_iterator is perfectly safe but since it does not follow the design of safe iterators in MSVC it will considered as unsafe.

Now you should either disable this warning by -D_SCL_SECURE_NO_WARNINGS to cl input flags or add a pragma to disable this warning( as you do ), but why pragma don't work?

the reason is obvious, this pragma work on scope and the scope that you use pragma on it have nothing wrong, you must guard xutility with this pragma and every thing will work as expected.