我得到了一个错误，我只能通过添加any作为返回值来修复它。
export const dbConnections: any = {};export const connectDb: Promise<void> = async () => {
if (dbConnections.isConnected) {
return;
}
try {
const db = await mongoose.connect(config.get('mongoURI'), {
useNewUrlParser: true,
useUnifiedTopology: true,
useFindAndModify: false,
useCreateIndex: true,
});
dbConnections.isConnected = db.connections[0].readyState;
} catch (err) {
createError('Error caught connecting to db!', err);
}};复制这会抛出一个错误，
export const connectDb: Promise<void> = async () => {
^^^^^^^^^^^^^Type '() => Promise<void>' is missing the following properties
from type 'Promise<void>': then, catch, [Symbol.toStringTag], finally复制如果我使用any而不是Promise<void>，那么这个错误就会消失，但这显然不是我想要做的。我如何修复这个lint错误？
问题在函数声明中。您需要将返回类型指定为Promise<void>。
export const connectDb = async (): Promise<void> => {
if (dbConnections.isConnected) {
return;
}
try {
const db = await mongoose.connect(config.get('mongoURI'), {
useNewUrlParser: true,
useUnifiedTopology: true,
useFindAndModify: false,
useCreateIndex: true,
});
dbConnections.isConnected = db.connections[0].readyState;
} catch (err) {
createError('Error caught connecting to db!', err);
}};typescript中的异步函数返回promise值。
如下所示：
export const dbConnections: any = {};export const connectDb: () => Promise<void> = async () => {
...};